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4∫ （lnx)²dx=? 3请老师详解http://www.jiandan100.cn/bbs/upload/viewthread.php?tid=636482&page=1#pid1985486
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teachercxy：∫(lnx)^2dx =x(lnx)^2-∫xd(lnx)^2 =x(lnx)^2-∫x*2*lnx*1/xdx =x(lnx)^2-2∫lnxdx =x(lnx)^2-2xlnx+2∫xdlnx =x(lnx)^2-2xlnx+2∫x*1/xdx =x(lnx)^2...(2012-04-04 19:15)
