f(x)=(2^x-1)(2^x+1),解不等式f(x)<3/5。
回复(2) 2011-07-02 06:53 来自版块 - 
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teachersongzhu解析:不等式f(x)<3/5可化为 (2^x-1)(2^x+1)<3/5 5(2^x-1)<3(2^x+1) 2×2^x<8 2^x<4 x<2 ∴不等式的解集为{x|x<2}.(2011-07-02 07:02)
teachergyyjzh(2011-07-02 07:00)

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