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已知f(x)=asin2x+btanx+1，且f(-2)=4,那么f(π+2)=???

回复(1) 2009-02-04 20:47 来自版块 -

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: xp117：f(-2)=asin(-4)+btan(-2)+1 =-asin4-btan2+1=4 asin4+btan2=-3 f(π+2)=asin(2π+4)+btan(π+2)+1 =asin4+btan2+1 =-3+...(2009-02-04 21:49)

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