f(a)=sina^2+sin(a+α)^2+sin(β+a)^2.其中0<α≤β≤2 π(圆周率). 试问α β各取值何值时,f(a)的值恒为常数
回复(1) 2011-10-07 13:41 来自版块 - 
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teacherzhyf(θ)=sin²θ+sin²(θ+α)+sin²(θ+β) =[1-cos(2θ)]/2+[1-cos(2θ+2α)]/2+[1-cos(2θ+2β)]/2=3/2-[cos(2θ)+cos(2θ+2α)+cos(2θ+2β)]/2 即3-2f(θ)=cos(2θ)+cos...(2011-10-07 13:47)

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