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求三次方程

2x3-3x2+1=0

回复(1) 2009-07-29 18:13 来自版块 -

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: teacher2：解答：2x^3-3x^2+1 =2x^3-2x^2-(x^2-1) =2x^2(x-1)-(x-1)(x+1) =(x-1)(2x^2-x-1) =(2x+1)(x-1)^2 =0， x=1或-1/2。(2009-07-30 10:05)

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