[题目讨论]一道数学好题，，不看后悔！！！！！！

已知sin(x+π/3)=1/4,求sin(2π/3-x)+cos²(π/6-x)






















sin(2π/3-x)+cos²(π/6-x)=sin[π-(2π/3-x)]+sin²[π/2-（π/6-x）]
 =sin(x+π/3)+sin²(x+3/π)
 =1/4+(1/4)²
=5/16

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